
<action; statement input; statement: i have a |ogic puzz|e for you input; statement: you have a 3-unit |iquid ho|der & a 5-unit |iquid ho|der. action; query input; query: how do you measure exact|y 4 units? />

<action; statement input; statement: that is not how that works />
butt tthatt wouldntt matttter rightt? cause if you pour 3 intto a 5, and tthen pour anotther of tthe 3, itt wontt be able tto hold tthe lastt unitt, so i know itts one unitt. aftter i emptty tthe fivve, i can pour in tthe 1 unitt i can be certtain of, and tthen use tthe 3 tto make 4

<action; statement input; statement: correct! input; statement: that is 1 way of doing it! />

<action; statement input; statement: for a reason! />

Pretty simple. Assuming there's a supply of liquid to work with. Pour Two instances of 3 Units into 5 until full. This leaves one unit in 3. Pour out 5, then pour the 1 unit in 5. Then pour 3 into 5.

<action; statement input; statement: correct! input; statement: that is 1 way of doing it />
ᐖ ERMMM HOL ON I GAWᐖᐖA FINK ABOUT ᐖIS FILL 3...AN ᐖEN POUR IT INTO 5. FILL 3 AGAIN. AN ᐖEN POUR AS MUᑈH INTO 5 AS U ᑈAN. WHIᑈH WILL BE 2. NOW ᐖERE'S 1 LEFT IN 3. POUR OUT 5. POUR 3 (WHIᑈH STILL HAS 1) INTO 5. FILL UP 3. POUR 3 INTO 5. NOW U HAV 4 ᐛ

<action; statement input; statement: correct! />
ᐖ YAY YAY YIPPEE #ᑈLAIRGESMORT ᐛ
